∠BGC = 2x = 90° Let r1 is the radius of the bigger circle = 5 cm. r2 is radius of the smaller circle = 3 cm Distance between both the centers of the circle d = 24 x =
dr2
r1+r2
x =
(24).(3)
5+5
=
72
8
= 9
x = 9 By using the length of the transversal tangent = √(d−x)2−r12 + √x2−r22 = l l = √(2−9)2−(5)2 + √(9)2−(3)2 = √255−25+√81−9 = √200+√72 = 16√2