CD = 6 cm OQ ⊥ CD CQ = QD = 3 cm. OC = OB = 5 = radius. In Δ OPB and Δ OQC (OP)2 = (OB)2−(PB)2 or (OQ)2 = (OC)2−(CQ)2 (OP)2 = (5)2−(4)2 or OQ2 = (5)2−(3)2 OP2 = 25 - 16 or OQ2 = 25 - 9 OP = √9 or OQ = √16 OP = 3 cm OQ = 4 cm OP + OQ = PQ PQ = 3 + 4 = 7 cm