We have a circle with radius 5 cm. PQ = 6 cm Length of TP = x By using Pythagoras theorem, ΔPMO (OM)2+(PM)2 = OP2 (3)2OM2 = (5)2 OM = √25−9 OM = √16 = 4 cm Let ∠POM = Q Let TP = x
Using Trigonometric ratio on ΔPMO and ΔPOT, we get tan θ =