Suppose length and breadth of the rectangular field are 11x m and 8x m. ∴ Perimeter of the field = 2(11x + 8x) = 2 × 19x = 38x m. Now, 38x = 760 ⇒ x =
760
38
= 20 ∴ Length of the field = 11 × 20 = 220 m Breadth of the field = 8 × 20 = 160 m ∴ Area of the field = 220 × 160 = 35200 sq. m.