Concept:Implicit differentiation using logarithms.Explanation:Take natural log of both sides: ylnx=x−y.Differentiate implicitly: xy+dxdylnx=1−dxdy.Bring dxdy terms together: dxdy(lnx+1)=1−xy.Thus dxdy=1+lnx1−xy.Evaluate at (1,1): ln1=0, so dxdy=1+01−1=0.Answer:dxdy at (1,1) is 0.