Probability

Concept:For a number to be divisible by 4, its last two digits must be divisible by 4.Explanation:Total 4‑digit numbers formed from digits 1,2,4,6 without repetition: $4! = 24$.Last two digits that are divisible by 4 (using two distinct digits): 12, 16, 24, 64 — that is 4 possibilities.For each such pair, the remaining two digits can be arranged in the first two places in $2! = 2$ ways.So favorable outcomes = $4 \times 2 = 8$.Probability = $\frac{8}{24} = \frac{1}{3}$.Answer:$\frac{1}{3}$