Probability

Concept:Use hypergeometric probability to find "at most 1 defective" in a sample of 4 from 10 components with 2 defectives.Explanation:Total ways to select any 4 from 10: $\binom{10}{4} = 210$.Number of non‑defective (good) components: $10 - 2 = 8$.Case 1: 0 defective (all 4 good): $\binom{8}{4} = 70$.Case 2: exactly 1 defective: choose 1 defective from 2 and 3 good from 8: $\binom{2}{1} \times \binom{8}{3} = 2 \times 56 = 112$.Total favorable outcomes: $70 + 112 = 182$.Probability = $\frac{182}{210} = \frac{13}{15}$.Answer:$\frac{13}{15}$