The equations are equivalent to;b=ac,a=bc+23,a=cbRaise each side of the second equation to the power of c. Then b=bc2+23c, so we must have 1=c2+23c (since b>1 for the logarithms to make sense). This has solutions c=−2 or c=−21, but we know c>0 so c=21. The remaining equations read a=b2 and a=2−b. Sketch both curves;
There is exactly one positive solution. The answer is (a)