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NTSE Stage 2 SAT 2019 Exam Question Paper
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© examsnet.com
Question : 72
Total: 100
A pin AB of length 2 cm is kept on the axis of a convex lens between 18 cm and 20 cm as shown in figure. Focal length of convex lens is 10 cm. Find magnification produced for the image of the pin.
0.83
1.00
1.25
6.78
Validate
Solution:
For the end B, image distance of end B will be,
f
=
10
c
m
u
B
=
−
18
c
m
v
B
=
image distance of end B
As we know,
1
f
=
1
v
B
−
1
u
B
1
v
B
=
1
f
+
1
u
B
1
v
B
=
1
10
−
1
18
=
8
180
v
B
=
180
8
⇒
22.5
c
m
Similarly, for the end A, image distance of end A will be,
f
=
10
c
m
u
A
=
−
20
c
m
v
A
=
image distance of end A
1
f
=
1
v
A
−
1
u
A
1
v
A
=
1
f
+
1
u
A
1
v
A
=
=
1
10
−
1
20
=
1
20
v
A
=
20
c
m
So,length of image
A
′
B
′
=
v
B
−
v
A
=
22.5
−
20
=
2.5
cm
So magnification ,
m
=
A
′
B
′
A
B
⇒
2.5
2
=
1.25
© examsnet.com
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