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NTSE Stage 2 SAT 2019 Exam Question Paper
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© examsnet.com
Question : 64
Total: 100
Two cars 'A' and ‘B’ of same mass start from the same location at the same time out on different straight roads. Car 'A' travels on a road that has greater angle of inclination with horizontal compared to the road on which 'B' Travels.
At any instant both cars 'A ’ and ‘B’ have the same height above the starting point. If
E
A
and
E
B
are total energies of cars ‘A* and 'B ' respectively, then
E
A
<
E
B
E
A
=
E
B
E
A
>
E
B
Relation between
E
A
and
E
B
cannot be decided based on given information.
Validate
Solution:
Since cars A and B are at same height above the starting point.
∴
h
=
1
2
a
A
s
i
n
θ
A
t
2
=
1
2
a
B
s
i
n
θ
B
t
2
a
A
a
B
=
s
i
n
θ
B
s
i
n
θ
A
Given,
s
i
n
θ
A
>
s
i
n
θ
B
∴
a
A
a
B
<
1
∴
a
A
<
a
B
.....(1)
Along the plane,
v
A
=
a
A
×
t
v
B
=
a
B
×
t
.....[Using (1)]
∴
v
A
v
B
=
a
A
a
B
<
1
........[Using (i)]
∴
v
A
<
v
B
T
⋅
E
A
=
m
g
h
+
1
2
m
v
A
2
T
⋅
E
B
=
m
g
h
+
1
2
m
v
B
2
At a given instant, height is same so potential energywill be same. But due to large speed of B, kinetic energy of B will be more.
∴
T
⋅
E
B
>
T
⋅
E
A
© examsnet.com
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