The exclusive NOR and exclusive OR of x and y is given by the expressions x ◉ y = xy + x'y' (exclusive NOR or XNOR) x ⊕ y = xf y + xy' (exclusive OR or XOR) So, option (A) is automatically true. Option (B)is x ⊕ y' which evaluates to x' y' + x(y')' = x'y' + xy which is equivalent to x ⊙ y. Option (C) is x' ⊕ y which evaluates to (x')'y + x' y' = xy + x' y' which is equivalent to x ⊙ y Option (D) is x ' ⊕ y ' which evaluates to (x')'y' + x'(y')' = xy' + x'y which is not equivalent to x ⊙ y.