Given equations of line are x + (a - 1) y + 1 = 0 ... (i) and 2x + a2y - 1 = 0 ... (ii) Since, line (i) and line (ii) are perpendicular ∴ Slope of line 1 x Slope of line 2 = -1 ∴ Slope of line x + (a - 1) y + 1 = 0 m1 =
−1
a−1
and slope of line 2x + a2y - 1 = 0 m2 =
−2
a2
m1m2 = - 1 ∴
1
(a−1)
2
a2
= - 1 ⇒ 2 = - a2 (a - 1) ⇒ 2 = −a3+a2 ⇒ a3+a2 - 2 = 0 ... (iii) On solving Eq. (in), we get a = - 1