logx2log2x2=log4x2∵logx2=log2x1,log2x2=log2(2x)1 and log4x2=log2(4x)1⇒log2x1∗log2(2x)1=log2(4x)1⇒log2xlog2(2x)=log2(4x)⇒log2x(log22+log2x)=log24+log2x Let log2x be a , ⇒a(1+a)=log222+a(∵log22=1)⇒a+a2=2+a⇒a=±2⇒log2x=±2⇒x=22,2−2