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NIMCET 2011 Question Paper with solutions

Directions (a. Nos. 46-48) Read the information given below and answer the questions that follow. Four persons

A, B, C

and D play a cards game. They put ₹ 500 as stake money. When the game is over 'C' receives

₹ 19

more that 'D' and 'B' receives

₹ 21

less than 'A' whose amount was

₹ 2

less than the quarter of

₹ 500

Question : 46 of 120

Marks: +1, -0

How much money did 'C' get?

Solution:

A's amount

= 500 \times \; \frac{1}{4} - 2 = \text{₹} 123

\therefore B'

s amount

= 2123 - \text{₹} 21 = \text{₹} 102

(A' S + B')

amount

= \text{₹} 123 + \text{₹} 102 = \text{₹} 225

Remaining armount

= \text{₹} 500 - \text{₹} 225 = \text{₹} 275

\therefore \;\; D'

amount

= \text{₹} 128

\therefore \;\; C' s

amount

= \text{₹} 128 + \text{₹} 19 = \text{₹} 147

C' s

amount

= \text{₹} 147

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