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Class 11 NEET Physics Physical World, Units and Measurements
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© examsnet.com
Question : 2
Total: 67
The pitch of an error free screw gauge is
1
mm
and there are 100 divisions on the circular scale. While measuring the diameter of a thick wire, the pitch scale reads
1
mm
and
63
rd
division on the circular scale coincides with the reference line. The diameter of the wire is:
[NEET 2024 Re]
1.63
cm
0.163
cm
0.163
m
1.63
m
Validate
Solution:
Least count of screw gauge
=
Pitch
No. of divisions on circular scale
⇒
Least count
=
1
100
=
0.01
mm
Final reading
=
MSR
+
CSR
×
L.C.
=
1
mm
+
(
63
)
(
0.01
)
mm
=
1.63
mm
=
0.163
cm
© examsnet.com
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