A capacitor of capacitance ' C ', is connected across an ac source of voltage V, given by V=V_{0} \sin \\omegat The displacement current between the plates of the capacitor, would then be given by [NEET 2021]

Correct Answer is : Id=V0εCcosωt

I_{d}=V_{0} \\epsilonC \cos \\omegat

I_{d}={V_{0}}/{\\omega C} \cos \\omegat