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Class 12 NEET Physics Electromagnetic Induction and Alternating Currents 2

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Question : 8 of 23

Marks: +1, -0

A B

is a part of an electrical circuit (see figure). The potential difference "

V_A - V_B

", at the instant when current

i = 2 \text{A}

and is increasing at a rate of

\frac{1 \text{amp}}{\text{second}}

9 volt
10 volt
5 volt
6 volt

Solution: 👈: Video Solution

\text{ Given, } I = 2 \text{A} \text{ and } \frac{di}{dt} = +1 \frac{\text{A}}{\text{s}}

V_A - L \frac{di}{dt} - 5 - i \times 2 = V_B

\Rightarrow V_A - 1 \times 1 - 5 - 2 \times 2 = V_B

\Rightarrow V_A - V_B = 10 \text{ volt }

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