Number of initial active nuclei=4×1016 Number of decayed nuclei after 10 days (half life) +=
4×1016
2
=2×1016 Remaining number of nuclei after 10 days =4×1016−2×1016=2×1016. ∴ Number of decayed nuclei in next 10 days =2×10162=1×1016 Similarly, number of decayed nuclei in next 10 days =0.5×1016 ∴ Total number of nuclei decayed after 30 days =2×1016+1×1016+0.5×1016=3.5×1016.