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NEET Exam Model Paper 6

Question : 7 of 180

Marks: +1, -0

t=0

Solution:

∵ At any angular position θ

T - mg\cos\theta = \frac{mv^2}{r}

\Rightarrow T = mg\cos\theta + \frac{mv^2}{r}

When mass is released from displaced position, θ starts decreasing and ‘v’ starts increasing. As result mg

\cos\theta

as well as

\frac{mv^2}{r}

both increases. Hence graph will be (d), (c) is not acceptable because at

t=0, T \neq 0

(b) is not acceptable because the variation is not linear.

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