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Question : 124 of 180

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Steam at 100°C is passed into 20 g of water at 10°C. when water acquires a temperature of 80°C, the mass of water present will be: ( Take specific heat of water =1calg−1°C−1 and latent heat of steam =540calg−1)

24 g
31.5 g
42.5 g
22.5 g

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