Test Index

Class 11 NEET Chemistry Some P block Elements Questions

Section: Chemistry

Question : 4 of 63

Marks: +1, -0

Nitrogen can form $\mathrm{p}\pi-\mathrm{p}\pi$ multiple bonds with itself.
$\;\;\;\mathrm{P}(\mathrm{C}_2\mathrm{H}_5)_3$ and $\mathrm{As}(\mathrm{C}_6\mathrm{H}_5)_3$ form $\mathrm{d}\pi-\mathrm{d}\pi$ bond with transition metals.
Phosphorus, arsenic and antimony show catenation property.
Nitrogen can form $\mathrm{d}\pi-\mathrm{p}\pi$ bond with oxygen.

Solution:

Concept:

Nitrogen (period 2) lacks d-orbitals and cannot participate in

\mathrm{d}\pi-\mathrm{p}\pi

bonding.

Chemical Equation / Formula:

Not applicable.

Explanation:

Option A is correct: Nitrogen can form

\mathrm{p}\pi-\mathrm{p}\pi

multiple bonds, e.g.,

\mathrm{N}\equiv\mathrm{N}

Option B is correct:

\mathrm{P}(\mathrm{C}_2\mathrm{H}_5)_3

and

\mathrm{As}(\mathrm{C}_6\mathrm{H}_5)_3

have vacant d-orbitals, enabling

\mathrm{d}\pi-\mathrm{d}\pi

interactions with transition metals.

Option C is correct: Phosphorus, arsenic, and antimony exhibit catenation, though it is less extensive than carbon.

Option D is incorrect: Nitrogen (and oxygen) do not possess d-orbitals, so no

\mathrm{d}\pi-\mathrm{p}\pi

bond is possible between them.

Thus, the incorrect statement is D.

Answer:

Go to Question:

Prev Question

Next Question