1.00\,{L} at {NTP} contains (1988)

Correct Answer is : all of the above.

Correct Answer is : all of the above.

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Class 11 NEET Chemistry Some Basic Concepts Of Chemistry

Question : 67 of 67

Marks: +1, -0

1.00\,\text{L}

\text{NTP}

Solution:

As we know

22400\,\text{cc}

\mathrm{N}_{2}\mathrm{O}

contain

6.02 \times 10^{23}

molecules

∴ 1 cc of

\mathrm{N}_{2}\mathrm{O}

contain

\frac{6.02 \times 10^{23}}{22400}

molecules

since in

\mathrm{N}_{2}\mathrm{O}

molecule there are 3 atoms

\therefore 1\,\text{cc}\,\mathrm{N}_{2}\mathrm{O}=\frac{3 \times 6.02 \times 10^{23}}{22400}

atoms

=\frac{1.8 \times 10^{22}}{224}

atoms

No. of electrons in a molecule of

\mathrm{N}_{2}\mathrm{O}=7+7+8=22

Hence, no. of electrons

=\frac{6.02 \times 10^{23}}{22400} \times 22

electron

=\frac{1.32}{224} \times 10^{23}

electrons

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