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Class 11 NEET Chemistry Redox Reactions Questions

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Question : 3 of 30

Marks: +1, -0

Consider the following compounds:

\underline{\mathrm{K}}O_2 ,\mathrm{H}_2 \underline{\mathrm{O}}_2

\mathrm{H}_2 \underline{\mathrm{S}} \mathrm{O}_4

The oxidation state of the underlined elements in them are, respectively,

$+1,-2$ , and +4
$+4,-4$ , and +6
$+1,-1$ , and +6
$+2,-2$ , and +6

Solution: 👈: Video Solution

\mathrm{KO}_2 \;\; \longrightarrow \;\;

Alkali metal always shows +1 oxidation state. Therefore oxidation state of K is +1 .

\mathrm{H}_2 \mathrm{O}_2 \;\; \longrightarrow

Oxidation state of oxygen in

\mathrm{H}_2 \mathrm{O}_2

is -1 .

\mathrm{H}_2 \mathrm{SO}_4 \;\; \longrightarrow

Oxidation state of sulphur in

\mathrm{H}_2 \mathrm{SO}_4

is +6 .

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