Current (I)=5 ampere and time (t)=40 minutes =2400 seconds. Amount of electricity passed (Q)=I×t=5×2400=12000C Now , Zn2++2e−→Zn(1‌mole=65.39) since, two charges (i.e., 2×96500 C) deposits 65.39‌gm of zinc, therefore 12000 C will deposit =