Consider the following relations for emf of an electrochemical cell (i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode) Which of the above relations are correct? (2010 Mains)

Question

Examsnet · Accepted Answer

Correct Answer is : (ii) and (iv)

Class 12 NEET Chemistry Electrochemistry Questions