Class 12 NEET Chemistry D And F Block Elements Questions

Concept:The spin-only magnetic moment is calculated using the number of unpaired electrons in the $d$-orbital.Chemical Equation / Formula:$\mu = \sqrt{n(n+2)}$ B.M. where $n$ = number of unpaired electrons.Explanation:For $\mathrm{Ti}^{2+}$, the atomic number of Ti is 22.Neutral Ti: $[\mathrm{Ar}]\,4s^2\,3d^2$.Remove two electrons (loss of $4s^2$): $\mathrm{Ti}^{2+} = [\mathrm{Ar}]\,3d^2$.In the $3d^2$ configuration, the two electrons occupy different orbitals (Hund's rule), giving $n = 2$ unpaired electrons.Substitute $n = 2$ into the formula: $\mu = \sqrt{2(2+2)} = \sqrt{8} = 2.84$ B.M.Answer:2.84 B.M. (Option C)