Test Index

NDA Math Limit, Continuity and Differentiability

Show Para  Hide Para 
Consider the following for the next three (03) items that follow:
Let f(x)={−2,−3≤x≤0x−2,0<x≤3f(x)=\begin{cases} -2, & -3 \le x \le 0 \\ x-2, & 0 < x \le 3 \end{cases} and g(x)=f(∣x∣)+∣f(x)∣g(x)=f(|x|)+|f(x)|
[NDA II 2016]
© examsnet.com
Question : 62 of 105
Marks: +1, -0
Go to Question: