MHTCET 26 Apr 2025 Shift 2 Paper

Concept:Torque on a current-carrying loop in a uniform magnetic field depends on the loop’s area: $\tau = IAB\sin\theta$.Explanation:For a loop, the torque is given by $\tau = I A B \sin\theta$.Here, $I$ is the current, $A$ is the area of the loop, $B$ is the magnetic field, and $\theta$ is the angle between the field and the normal to the loop.The current $I$, magnetic field $B$, and angle $\theta$ are the same for both loops.So, the torque depends only on the area $A$ of the loop.Both wires have equal lengths, meaning the perimeter of the square equals the circumference of the circle.For the same perimeter, the area of a circle is larger than the area of a square.Since $A_{\text{circle}} > A_{\text{square}}$, we get $\tau_{\text{circle}} > \tau_{\text{square}}$.Therefore, the circular loop experiences greater torque than the square loop.Answer:Torque experienced by the circular loop is maximum.So, the correct option is D. circular loop is maximum.