A manufacturing company produces two items, A and B. Each toy should be processed by two machines, I and II. Machine I can be operated for maximum 10 hours 40 minutes. It takes 20 minutes for an item of A and 15 minutes for B. Machine II can be operated for a total time at 8 hours 20 minutes. It takes 5 minutes for an item A and 8 minutes for B . The profit per item of A is R s 25 and per item of B is ₹ 18 . The formulation of an L.P.P. to maximize the profit (where x is number of items A and y is the number of item B ) is

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Correct Answer is : Maximize z=25x+18yz=25 x+18 yz=25x+18y subject to 20x+15y≤6405x+8y≤500x,y≥0 { subject to } {aligned}
20 x+15 y & ≤ 640 \
5 x+8 y & ≤ 500 \
x, y & ≥ 0
{aligned} subject to 20x+15y5x+8yx,y​≤640≤500≥0​

\text { Maximize }	$\mathrm{z}=25 x+18 y$
\text { subject to }	$20 x+15 y \leq 640$
	$5 x+8 y \geq 500$
	$x, y \geq 0$

$\text { Maximize }$	$z=25 x+18 y$
$\text { subject to }$	$20 x+5 y \leq 8$
	$5 x+8 y \leq 10$
	$x, y \geq 0$

MHTCET 26 Apr 2025 Shift 2 Paper