Concept:Divide numerator and denominator by the highest power, (2x)50, then apply the limit term by term.Explanation:The given limit is: x→∞lim(2x)50+(10)50∑k=1100(2x+k)50 Divide both numerator and denominator by (2x)50: =x→∞lim1+(2x10)50∑k=1100(1+2xk)50 As x→∞, we have 2xk→0 and 2x10→0. So each term (1+2xk)50→150=1. There are 100 such terms in the numerator, giving 100×1=100. The denominator tends to 1+0=1. Therefore, the limit is 1100=100.Answer:100