MHTCET 25 Apr 2025 Shift 1 Paper

Concept:The constraints define a feasible region in the first quadrant bounded by the lines $|x-y| = 1$.Explanation:The inequality $|x-y| \leq 1$ means $-1 \leq x-y \leq 1$.This gives two boundary lines: $x-y = 1$ and $x-y = -1$.With $x, y \geq 0$, the region lies in the first quadrant.The strip between $x-y = 1$ and $x-y = -1$ extends infinitely along the positive $x$ and $y$ directions.So the feasible region has no upper bound and is not closed.Answer:B. an unbounded set