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MHTCET 23 Apr 2025 Shift 1 Paper

Question : 34 of 150

Marks: +1, -0

A current of 5 A is flowing at 220 V in a primary coil of a transformer. If the voltage produced in the secondary coil is 2200 V and 50\% of power is lost, then the current in the secondary coil will be

Solution:

Concept:

Transformer power depends on the product of current and voltage, with power loss reducing the available secondary power.

Explanation:

Primary power is

P_p = I_p V_p = 5 \times 220 = 1100\ \text{W}

Since

50\%

power is lost, secondary power is

P_s = \frac{1100}{2} = 550\ \text{W}

Using

P_s = I_s V_s

, we get

I_s = \frac{P_s}{V_s} = \frac{550}{2200} = 0.25\ \text{A}

Answer:

I_s = 0.25\ \text{A}

, which matches option C.

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