Concept:Area bounded by a curve x=f(y) and the Y-axis is found by integrating f(y) between the limits of y.Explanation:Given curve: x=2−y−y2Y-axis means x=0.Put x=0: 0=2−y−y2⇒y2+y−2=0⇒(y+2)(y−1)=0So y=−2 and y=1.These are the limits of integration.Required area =∫−21(2−y−y2)dy=[2y−2y2−3y3]−21At y=1: 2−21−31=67At y=−2: −4−2+38=−310Area =67−(−310)=67+620=627=29Answer:29 sq. unitsCorrect option: C.