MHTCET 19 Apr 2026 Shift 2 Paper

Concept:This reaction involves nucleophilic substitution followed by reduction of a nitrile to a primary amine.Explanation:$\mathrm{CH}_{3}\mathrm{Br}$ reacts with $\mathrm{KCN}$ to give ethanenitrile, $\mathrm{CH}_{3}\mathrm{CN}$, as product $A$.This happens because the cyanide ion ($\mathrm{CN}^-$) replaces bromine and adds one carbon atom to the chain.Then, $\mathrm{CH}_{3}\mathrm{CN}$ is reduced by sodium in ethanol.The nitrile group ($-\mathrm{CN}$) is reduced to a primary amine group ($-\mathrm{CH}_{2}\mathrm{NH}_{2}$).So, product $B$ is $\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{NH}_{2}$, which is ethanamine.Answer:Option B: Ethanamine.