Concept:Use implicit differentiation to find dxdy from the given relation between x and y.Explanation:Given equation: 3y2−2xy−x=0.Substitute y=2 to find the corresponding value of x.3(2)2−2x(2)−x=012−4x−x=012−5x=0x=512Differentiate the given equation implicitly with respect to x.6ydxdy−2(xdxdy+y)−1=0(6y−2x)dxdy=2y+1dxdy=6y−2x2y+1Now substitute y=2 and x=512.dxdy=6(2)−2(512)2(2)+1=12−5245=5365=3625Answer:The value of dxdy at y=2 is 3625, i.e. Option C.