Identify general electronic configuration exhibited by 2^{ {nd }} series of transition elements.

Correct Answer is : [Kr] 4d1−105s0−24 d¹-10} 5 s^{0-2}4d1−105s0−2

Correct Answer is : [Kr] 4d1−105s0−24 d¹-10} 5 s^{0-2}4d1−105s0−2

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MHTCET 19 Apr 2026 Shift 1 Paper

Question : 82 of 150

Marks: +1, -0

2^{\text {nd }}

series of transition elements.

Solution:

Concept:

The second transition series corresponds to filling of the

4d

subshell, with the preceding noble gas core being krypton.

Explanation:

The elements from yttrium (

Y

, atomic number 39) to cadmium (

Cd

, atomic number 48) form the second transition series.

In this series, electrons are added progressively to the

4d

subshell, while the outermost shell is the fifth shell.

The general electronic configuration is written using the krypton core:

[\mathrm{Kr}]\, 4d^{1-10}\, 5s^{0-2}

The

5s

subshell shows variable occupancy, from

0

2

, due to exceptional configurations arising from stability considerations.

For example, palladium has

4d^{10}\,5s^{0}

, while most other elements follow

5s^{2}

5s^{1}

patterns.

Therefore, the configuration

[\mathrm{Kr}]\,4d^{1-10}\,5s^{0-2}

correctly represents all members of this series.

Answer:

Option B:

[\mathrm{Kr}]\, 4d^{1-10}\, 5s^{0-2}

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