MHTCET 18 Apr 2026 Shift 2 Paper

Concept:Identify each gate first; the bubble at the output gives the complement of the basic AND/OR gate.Explanation:The upper gate has inputs $A$ and $B$ and behaves as a NAND gate.For a NAND gate, the output is the complement of $A \cdot B$, so we get $\overline{A \cdot B}$.The lower gate has inputs $B$ and $C$ and behaves as a NOR gate.For a NOR gate, the output is the complement of $B+C$, so we get $\overline{B+C}$.The two outputs are then connected to the final OR gate.Therefore, the final output is the logical OR of these two intermediate outputs:$$Y = \overline{A \cdot B} + \overline{B+C}$$This exactly matches option C.Answer:$Y = \overline{(A \cdot B)} + \overline{(B+C)}$, i.e. option C.