MHTCET 18 Apr 2026 Shift 2 Paper

Concept:Inductors connected across the same pair of nodes are in parallel.Explanation:Mark the two terminals as Node A and Node B.A wire has zero resistance, so every point on the same continuous wire is at the same potential.The top wire connects Node A, the top end of the 2 H inductor, and the junction near the 4 H inductor. Hence, all these points are at Node A.The bottom wire connects the junction of the 1 H, 2 H, and 3 H inductors to Node B. Hence, all these points are at Node B.Now check each inductor:The 1 H inductor is connected between Node A and Node B.The 2 H inductor is connected between Node A and Node B.The 3 H inductor is connected between Node B and Node A.The 4 H inductor is connected between Node A and Node B.Therefore, all four inductors are connected across the same two terminals A and B, so they are in parallel.For inductors in parallel:$$\frac{1}{L_{eq}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3} + \frac{1}{L_4}$$Substitute the values:$$\frac{1}{L_{eq}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3} + \frac{1}{4}$$The LCM of 1, 2, 3, and 4 is 12.$$\frac{1}{L_{eq}} = \frac{12 + 6 + 4 + 3}{12} = \frac{25}{12}$$Taking the reciprocal:$$L_{eq} = \frac{12}{25} \, \mathrm{H}$$Answer:The equivalent inductance between A and B is $\frac{12}{25} \, \mathrm{H}$, which is option C.