Concept:A function can be applied to its own output by substituting the inner result into f(x) again.Explanation:Given f(x)=1+x1−x.First, find f(cosx) by replacing x with cosx:f(cosx)=1+cosx1−cosx.Now apply f again to this result:f(f(cosx))=1+1+cosx1−cosx1−1+cosx1−cosx.Simplify the numerator and denominator:Numerator: 1−1+cosx1−cosx=1+cosx(1+cosx)−(1−cosx)=1+cosx2cosx.Denominator: 1+1+cosx1−cosx=1+cosx(1+cosx)+(1−cosx)=1+cosx2.Dividing gives:f(f(cosx))=1+cosx21+cosx2cosx=cosx.Answer:Option A: cosx