MHTCET 17 Apr 2026 Shift 1 Paper

Concept:Dilute $\mathrm{KMnO}_{4}$ is a mild oxidising agent; it adds $-\mathrm{OH}$ groups across the double bond of an alkene to form a vicinal diol, which is a dihydric alkanol.Explanation:In the presence of dilute $\mathrm{H}_{2}\mathrm{SO}_{4}$, dilute $\mathrm{KMnO}_{4}$ oxidises the alkene gently.Each carbon atom of the $\mathrm{C}=\mathrm{C}$ double bond receives one hydroxyl group.This produces a vicinal diol (glycol).For example, ethene gives ethane-1,2-diol:$$\mathrm{CH}_{2}=\mathrm{CH}_{2} \xrightarrow[\text{dil. } \mathrm{H}_{2}\mathrm{SO}_{4}]{\mathrm{KMnO}_{4}} \mathrm{HO}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{OH}$$Since the product contains hydroxyl groups attached to an alkane framework, it is classified as an alkanol.Hot or concentrated acidic $\mathrm{KMnO}_{4}$ would cleave the carbon–carbon double bond to give ketones or carboxylic acids, but the dilute reagent stops at the diol stage.Answer:Option A — Alkanol.