Concept:The parent ring is a seven-membered cyclic alcohol, and the numbering must give the lowest locants to substituents, with alphabetical order deciding ties.
Explanation:The compound contains a seven-carbon ring with an
−OH group.
The
−OH group is the principal functional group, so the parent name is cycloheptanol.
The carbon bearing the
−OH is numbered as carbon 1.
This ring also has one ethyl group and one methyl group as substituents.
Numbering clockwise gives ethyl at position 3 and methyl at position 6.
Numbering anticlockwise gives methyl at position 3 and ethyl at position 6.
Both sets are
(3,6), so the locants are identical.
Therefore, alphabetical order is applied: ethyl (e) comes before methyl (m).
Thus, ethyl gets the lower locant (position 3) and methyl gets position 6.
The IUPAC name becomes 3-ethyl-6-methylcycloheptanol.
Answer:3-Ethyl-6-methylcycloheptanol
Hence, the correct option is C.
