MHTCET 16 May 2024 Shift 2 Paper

Concept:The cell constant of a conductivity cell is the product of the conductivity and the resistance of the solution.Explanation:The relationship between cell constant $(K)$, conductivity $(\kappa)$, and resistance $(R)$ is given by:$$K = \kappa \times R$$This equation directly gives the cell constant from the measured values.Here, the conductivity of the 0.1 M KCl solution is $\kappa = 0.014 \ \Omega^{-1} \mathrm{~cm}^{-1}$.The resistance offered by the solution is $R = 60 \ \Omega$.Substituting these values into the formula:$$K = 0.014 \ \Omega^{-1} \mathrm{~cm}^{-1} \times 60 \ \Omega$$The unit $\Omega^{-1}$ cancels with $\Omega$, leaving the unit of cell constant as $\mathrm{cm}^{-1}$.$$K = 0.84 \ \mathrm{~cm}^{-1}$$This matches the value given in option B.Answer:The cell constant of the conductivity cell is $0.84 \ \mathrm{~cm}^{-1}$, i.e., option B.