MHTCET 16 May 2024 Shift 1 Paper

Concept:Conductivity $(\kappa)$ is calculated from the cell constant and the measured resistance of the solution.Explanation:The relation between conductivity, cell constant, and resistance is:$$\kappa = \frac{\text{Cell constant}}{R}$$Given values are:$$R = 31.5 \, \Omega$$$$\text{Cell constant} = 0.315 \, \mathrm{cm}^{-1}$$Substitute these values into the formula:$$\kappa = \frac{0.315 \, \mathrm{cm}^{-1}}{31.5 \, \Omega}$$Simplifying the division:$$\kappa = 0.01 \, \Omega^{-1} \, \mathrm{cm}^{-1}$$The molar concentration of NaOH is not needed for this calculation because conductivity is directly obtained from resistance and cell constant.Therefore, the conductivity of the solution is $0.01 \, \Omega^{-1} \, \mathrm{cm}^{-1}$.Answer:Conductivity $= 0.01 \, \Omega^{-1} \, \mathrm{cm}^{-1}$, which matches Option D.