Concept:Simplify the given logical expression using standard equivalence laws.Explanation:Start with (∼p)∨(p∧∼q).Apply the distributive law: (∼p∨p)∧(∼p∨∼q).By the complement law, ∼p∨p≡T.So the expression becomes T∧(∼p∨∼q).Using the identity law, T∧A≡A, so we get ∼p∨∼q.Recall the implication equivalence: p→r≡∼p∨r.Taking r=∼q, we have ∼p∨∼q≡p→(∼q).Therefore, the given proposition is equivalent to p→(∼q).Answer:Option C: p→(∼q)