MHTCET 16 Apr 2026 Shift 2 Paper

Concept:This is a nucleophilic substitution reaction known as Williamson ether synthesis.Explanation:$\mathrm{CH}_3\mathrm{ONa}$ is sodium methoxide, which dissociates to give the methoxide ion $\mathrm{CH}_3\mathrm{O}^-$.$\mathrm{CH}_3\mathrm{CH}_2\mathrm{Br}$ is bromoethane, a primary alkyl halide.The methoxide ion acts as a strong nucleophile and attacks the electrophilic carbon bonded to bromine.Bromide ion is expelled as a leaving group.The reaction follows an $\mathrm{S_N2}$ mechanism.This produces methoxyethane, $\mathrm{CH}_3\mathrm{OCH}_2\mathrm{CH}_3$, along with sodium bromide, $\mathrm{NaBr}$.The balanced equation is:$$\mathrm{CH}_3\mathrm{ONa} + \mathrm{CH}_3\mathrm{CH}_2\mathrm{Br} \rightarrow \mathrm{CH}_3\mathrm{OCH}_2\mathrm{CH}_3 + \mathrm{NaBr}$$Therefore, the product is methyl ethyl ether.Answer:Option A: Formation of $\mathrm{CH}_3\mathrm{OCH}_2\mathrm{CH}_3 + \mathrm{NaBr}$.