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MHTCET 16 Apr 2026 Shift 1 Paper

Question : 2 of 150

Marks: +1, -0

Let

\vec{P}=\hat{i}+\hat{j}+\hat{k}

\vec{Q}=-(\hat{i}+\hat{j}+\hat{k})

(\vec{P}-\vec{Q})

\vec{P}

Solution:

Concept:

Two vectors that are scalar multiples of each other with a positive scalar have the same direction, so the angle between them is

0^\circ

Explanation:

Given:

\vec{P} = \hat{i}+\hat{j}+\hat{k}

and

\vec{Q} = -(\hat{i}+\hat{j}+\hat{k})

Therefore,

\vec{Q} = -\vec{P}

Now, compute

\vec{P}-\vec{Q}

\vec{P}-\vec{Q} = \vec{P}-(-\vec{P}) = \vec{P}+\vec{P} = 2\vec{P}

Since

\vec{P}-\vec{Q} = 2\vec{P}

, it points in the same direction as

\vec{P}

Hence, the angle between

(\vec{P}-\vec{Q})

and

\vec{P}

0^\circ

Answer:

Option C:

0^\circ

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