Concept:Use the identity sina=sin[x−(x−a)] to split the integrand into a difference of cotangents, which integrates directly.Explanation:Let I=∫cosec(x−a)⋅cosecxdx.I=∫sin(x−a)sinx1dx.Multiply numerator and denominator by sina:I=sina1∫sin(x−a)sinxsin[x−(x−a)]dx.Since sin[x−(x−a)]=sinxcos(x−a)−cosxsin(x−a), we get:I=sina1∫[cot(x−a)−cotx]dx.Integrating term by term,∫cot(x−a)dx=log∣sin(x−a)∣ and ∫cotxdx=log∣sinx∣.Therefore, I=sina1[log∣sin(x−a)∣−log∣sinx∣]+c.I=sina1logsinxsin(x−a)+c.I=sina1log∣sin(x−a)⋅cosecx∣+c.Answer:Option C: sina1log(sin(x−a)⋅cosecx)+c, where c is the constant of integration.