Identify from following the conjugate base of ≤ft[{Zn}≤ft({H}₂ {O})₄]²+}

Correct Answer is : [Zn(H2O)3OH]+≤ft[{Zn}≤ft({H}₂ {O})₃ {OH}]^{+}[Zn(H2O)3OH]+

≤ft[{Zn}≤ft({H}₂ {O})₄]²-} {NH}₃

≤ft[{Zn}≤ft({H}₂ {O})₃]²-}

≤ft[{Zn}≤ft({H}₂ {O})₃ {OH}]^{+}

≤ft[{Zn}≤ft({H}₂ {O}) {H}]³+}

Correct Answer is : [Zn(H2O)3OH]+≤ft[{Zn}≤ft({H}₂ {O})₃ {OH}]^{+}[Zn(H2O)3OH]+

Test Index

MHTCET 15 Apr 2026 Shift 2 Paper

Question : 62 of 150

Marks: +1, -0

\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{2+}

$\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{2-} \mathrm{NH}_{3}$
$\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\right]^{2-}$
$\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3} \mathrm{OH}\right]^{+}$
$\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{H}\right]^{3+}$

Solution:

Concept:

A conjugate base is formed when an acid loses one proton (

\mathrm{H}^{+}

Explanation:

The given complex is

[\mathrm{Zn}(\mathrm{H}_{2}\mathrm{O})_{4}]^{2+}

One coordinated water molecule can lose

\mathrm{H}^{+}

and become

\mathrm{OH}^{-}

So, the reaction is:

[\mathrm{Zn}(\mathrm{H}_{2}\mathrm{O})_{4}]^{2+} \rightarrow [\mathrm{Zn}(\mathrm{H}_{2}\mathrm{O})_{3}\mathrm{OH}]^{+} + \mathrm{H}^{+}

The charge of the complex changes from

+2

+1

after losing

\mathrm{H}^{+}

Thus, the conjugate base is

[\mathrm{Zn}(\mathrm{H}_{2}\mathrm{O})_{3}\mathrm{OH}]^{+}

Answer:

Option C:

[\mathrm{Zn}(\mathrm{H}_{2}\mathrm{O})_{3}\mathrm{OH}]^{+}

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