MHTCET 15 Apr 2026 Shift 2 Paper

Concept:At resonance in a series LCR circuit, the inductive and capacitive reactances cancel each other, making the circuit purely resistive.Explanation:At resonance, the inductive reactance equals the capacitive reactance:$$X_{L} = X_{C}$$So the net reactance becomes zero:$$X_{L} - X_{C} = 0$$The impedance of a series LCR circuit is given by:$$Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}$$Substituting $X_{L} - X_{C} = 0$, we get:$$Z = R$$This shows that impedance is minimum, not maximum.Since impedance is minimum, the current is maximum:$$I = \frac{V}{Z}$$Also, with zero net reactance, the circuit behaves like a purely resistive circuit.In a purely resistive circuit, the current and voltage are in phase with each other.Therefore, the correct option is D.Answer:Option D: the current and voltage are in phase.