The ball executes free fall until it hits the upper surface of glycerine. ∴ Velocity of ball when it reaches the upper surface of glycerine is given as, v‌=√2gh ‌=√2×9.8×1.5 ⇒‌‌v2‌=29.4m∕s2 Using the formula, v2−u2=2as inside the glycerine. We have, 0−29.4=−2×(2.66)×h (∵h= distance travelled inside glycerine) ⇒‌‌h=5.5m ∴ The height of glycerine in jar will be 5.5m.